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There are two circular flower beds on two sides of a square lawn ABCD of side 56 m. If the centre of each circular flower bed is the point of intersection of the diagonals of the square lawn, find the sum of the areas of the lawn and the flower beds.

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Side of square `ABCD=56 m`
`AC=BD`(diagonals of a square are equal in lengths)
Diagonal of square `(AC) =sqrt(2)xxbb"side square"`
`AC= sqrt(2)xx56=56sqrt(2)`
​ `OA=OB=1/2 AC=1/2 (56sqrt(2))=28sqrt(2)`
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