" (2) Selne the eq"."(9)/(x)-(b)/(y)=0,(ab^(2))/(x)+(a^(2)y)/(y)=a^(2)+b^(2)

(a)/(x)-(b)/(y)=0,(ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)

Solve : {:((a)/(x)-(b)/(y)=0),((ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)):}

Solve the following system of equations in x and y:(a)/(x)-(b)/(y)=0,quad (ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2) where x,y!=0

Solve the following pair of equations for x and y : (a^(2))/(x)-(b^(2))/(y)=0, (a^(2)b)/(x)+(b^(2)a)/(y)=a+b , x ne 0 , y ne 0 .

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}

Solve :a(x+y)+b(x-y)=a^(2)-ab+b^(2)a(x+y)-b(x-y)=a^(2)+ab+b^(2)

Solution to (a^2)/(x)-(b^2)/(y)=0, (a^2b)/(x)+(b^2a)/(y)=a+b,x ne0,y ne0 is………

If (x+1)/(x-1)=(a)/(b) and (1-y)/(1+y)=(b)/(a), then the value of (x-y)/(1+xy) is (2ab)/(a^(2)-b^(2)) (b) (a^(2)-b^(2))/(2ab) (c) (a^(2)+b^(2))/(2ab) (d) (a^(2)-b^(2)backslash)/(ab)