The following are the steps involved in finding the value of a when `x - 2` is a factor of `3x^(2)-7x+a`. Arrange them in sequential order.
(A) `12-14+a=0rArra=2`
(B) By factor theorem , `f(2)=0rArr3(2)^(2)-7(2)+a=0`
(C ) Let `f(x)=3x^(2)-7x+a`

If x-2 is a factor of x^(2)-7x+2a , find the value of a.

Find the factors of 2x^2+7x+3

Factors of 2x^2 + 7x + 3 are

The factors of 2x^2 - 7x + 3 are :

If A = (3,-4) , B= (7,0) and C = (14 , -7) are the three consecutive vertices of a parallelogram ABCD , then find the slope of the diagonal BD . The following are the steps involved in solving the above problem . Arrange them is sequential order (A) ((x + 7)/(2) , (y + 0)/(2)) = ((3 + 14)/(2) , (-4-7)/(2)) . (B) The slope of BD = (-11-0)/(10-7) = (-11)/(3) . (C) (x+7)/(2) = (17)/(2) and (y+0)/(2) - (-11)/(2) implies x = 10 , y = -11 therefore D = (10 , -11) . (D) Let the fourth vertex be D(x , y) . we know that the diagonals of a parallelogram bisect each other .

If (x-sqrt2) is a factor of x^4-7x^3+10x^2+14x-24 . Find the other factors.

Show that 2x + 7 is a factor of 2x^3 + 7x^2 - 4x - 14 Hence, solve the equation: 2x^3 + 7x^2 - 4x - 14 = 0.

Solve : (3x +4)/(7) - (x +5)/(14) = (x)/(28) + (x +1)/(14) The following steps are involved in solving the above problem. Arrange them in sequential order (A) 5x + 3 = (3x + 2)/(2) rArr 10 x + 6 = 3x + 2 (B) rArr 7x = -4 (C) Given (3x + 4)/(7) - (x + 5)/(14) = (x)/(28) + (x +1)/(14) rArr (6x + 8 -x -5)/(14) = (x + 2x + 2)/(28) (D) rArr x = -(4)/(7)