The slopes of the lines represented by `x^(2) + 2hxy + 2y^(2) = 0` are in the ratio 1 : 2, then find 'h'.

If the slopes of the lines represented by 6x^(2)+2hxy+y^(2)=0 are in the ratio 1:2 then h=

The slopes of lines represented by x^2+2hxy+2y^2=0 are in the ratio 1:2 , then h equals .

If the slopes of the lines represented by ax^(2)+2hxy+by^(2)=0 are in the ratio m:n then ((m+n)^(2))/(mn)=

If the slopes of the line given by 6x^(2)+2hxy+y^(2)=0 are in the ratio 1:2 , then h=

If the slopes of the lines given by ax^(2)+2hxy+by^(2)=0 are in the ratio 3:1 , then h^(2)=

If the slopes of the lines given by ax^(2)+2hxy+by^(2)=0 are in the ratio 3:1 , then h^(2)=

Find the value of h if the slopes of the lines represented by 6x^(2)+2hxy+y^(2)=0 are in the ratio 1:2.

If the slope of one of the lines represented by ax^(2) + 2hxy + by^(2) = 0 is the square of the other, then (a+b)/h+(8h^(2))/(ab)

If the slopes of the lines 3x^(2) + 2hxy + 4y^(2)=0 are in the ration 3:1 , then h equals