A particle `P` is projected upwards with `80m//s`. One second later another particle `Q` is projected with initial velocity `70m//s`. Before either of the particle srikes the ground `(g=10m//s^(2))`

A particle is projected from ground with initial velocity 3hati + 4hatj m/s. Find range of the projectile :-

A particle is projected upwards with velocity 20m//s . Simultaneously another particle is projected with velocity 20(sqrt2) m//s at 45^@ . (g = 10m//s^2) (a) What is acceleration of first particle relative to the second? (b) What is initial velocity of first particle relative to the other? (c) What is distance between two particles after 2 s?

A particle is projected upwards with velocity 20m//s . Simultaneously another particle is projected with velocity 20(sqrt2) m//s at 45^@ . (g = 10m//s^2) (a) What is acceleration of first particle relative to the second? (b) What is initial velocity of first particle relative to the other? (c) What is distance between two particles after 2 s?

The particle of mass 1 kg is projected with velocity 20sqrt(2) m/s at 45^(@) with ground . When , the particle is at highest point (g=10 m//s^(2)) ,

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

A particle P is projected Vertically upward from a point A . Six seconds later, another particle Q is projected vertically upward from A . Both P and Q reach A simultaneously. The ratio o f maximum heights reached by P and Q=65 : 25 . Find the velocity of the projection of Q in m//s .

A particle P is projected vertically upward from a point A. Six seconds later, another particle Q is projected vertically upward from A. Both P and Q reach A simultaneously. The ratio of maximum heights reached by P and Q=64:25.Find the velocity of the projection of Q in m/s.