(cos theta+i sin theta)^(n)=cos n theta+i sin n theta

If (cos theta + i sin theta)(cos 2 theta +i sin 2 theta ) …(cos n theta + i sin n theta)=1 then the value of theta is (m are integers)-

Prove the following by the method of induction for all n in N : (cos theta + i sin theta)^n = cos n theta + i sinntheta , where i = sqrt -1.

The number of values of theta in (0, pi] , such that (cos theta + i sin theta) (cos 3 theta + i sin 3 theta) (cos 5 theta + i sin 5 theta) (cos 7 theta + i sin 7 theta) (cos 9 theta + i sin 9 theta) = -1 is

The value of (1+cos theta+i sin theta)^(n)+(1+cos theta-i sin theta)^n=

The value of (1+cos theta+i sin theta)^(n)+(1+cos theta-i sin theta)^(n)=

The general value of theta which satisfies the equation (cos theta + i sin theta) (cos 3 theta + I sin 3 theta) ….. {cos(2n - 1) theta + I sin (2n - 1) theta} = 1 is

cos m theta-sin n theta=0

If ((1+cos theta+i sin theta)/(sin theta+i+i cos theta))^(4)=cos n theta+i sin n theta , then n=

If(cos theta+i sin theta)(cos2 theta+i sin2 theta).....(cos n theta+i sin n theta)=1 then the value of theta is: