" 21) "(a+b)^(2)-a-b)

What is the value of {((a+b)^(2) - (a^(2) +b^(2)))/((a+b)^(2) - (a-b)^(2))}?

The factors of 8a^3+b^3-6a b+1 are (a) (2a+b-1)(4a^2+b^2+1-3a b-2a) (b) (2a-b+1)(4a^2+b^2-4a b+1-2a+b) (c) (2a+b+1)(4a^2+b^2+1-2a b-b-2a) (d) (2a-1+b)(4a^2+1-4a-b-2a b)

Find the sum of the following series: (a-b)62+(a^(2)+b^(2))+(a+b)^(2)++[(a+b)^(2)+6ab]

Simplify: a^2b(a-b^2)+a b^2(4a b-2a^2)-a^3b(1-2b)

If tantheta=a/b , then (asintheta+bcostheta)/(asintheta-bcostheta) is equal to (a) (a^2+b^2)/(a^2-b^2) (b) (a^2-b^2)/(a^2+b^2) (c) (a+b)/(a-b) (d) (a-b)/(a+b)

If cosalpha+cosbeta=a, sinalpha+sinbeta=b, then cos(alpha+beta) is equal to (A) (2ab)/(a^2+b^2) (B) (a^2+b^2)/(a^2-b^2) (C) (a^2-b^2)/(a^2+b^2) (D) (b^2-a^2)/(b^2+a^2)