sin5n cos3n=sin9x*cos7x

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Find the general solution of sin5x cos 3x = sin9x cos7x

sin5x cos3x = sin 9x cos7x

Prove that (sin9x+sin7x+sin3x+sin5x) /(cos9x+cos7x+cos3x+cos5x)=tan6x ?

Prove that (sin 9x+sin7+sin 3x+sin 5x)/(cos 9x+ cos 7x+ cos 3x+cos 5x)=tan 6x .

(sin3A+sin5A+sin7A+sin9A)/(cos3A+cos5A+cos7A+cos9A)

If x=(pi)/(48); then the value of (sin7x+sin5x+sin9x+sin3x)/(cos7x+cos5x+cos9x+cos3x) equals to

The fundamental period of (sin x+sin3x+sin5x+sin7x)/(cos x+cos3x+cos5x+cos7x) is (pi)/(k) then k=

(sin3A+sin5A+sin7A+sin9A)/(cos3A+cos5A+cos7A+cos9A)=tan6A

Prove that: (sin3A+sin5A +sin7A+sin9A)/(cos3A+cos5A+cos7A+cos9A)=tan6A