`(costheta+cos3theta)/(sintheta-sin3theta)` is equal to:

(3costheta+cos3theta)/(3sintheta-sin3theta)=

costheta-cos2theta=sin3theta

The value of (cos^(3)theta+sin^(3)theta)/(costheta+sintheta)+(cos^(3)theta-sin^(3)theta)/(costheta-sintheta) is equal to

(sin3theta-cos3theta)/(sintheta+costheta)+1 =

(sin5theta+sin2theta-sintheta)/(cos5theta+2cos3theta+2cos^2theta+costheta) is equal to

int (cos2theta) . log((costheta+sintheta)/(costheta-sintheta))d theta is equal to

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1