" "I') "int(tan x+tan alpha)/(tan x-tan alpha)dx

Let alpha in (0, pi/2) be fixed. If the integral int(tan x + tan alpha)/(tan x - tan alpha)dx = A(x)cos 2 alpha+B(x) sin 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

Let alpha in (0, pi//2) be fixed. If the integral int("tan x" + "tan" alpha)/("tan x" - "tan" alpha)dx = A(x)"cos 2 alpha+B(x) "sin" 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

Let alpha in (0, pi//2) be fixed. If the integral int("tan x" + "tan" alpha)/("tan x" - "tan" alpha)dx = A(x)"cos 2 alpha+B(x) "sin" 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

int (tan x-tan x//2)/(1+ tan x tan x//2)dx=

" (.) "int(tan x)/(1+tan x)dx

If sin(x+3 alpha)=,3sin(alpha-x) then (A) tan x,=tan alpha (B) tan x,=tan^(2)alpha (C) tan x,=tan^(3)alpha (D) tan x,=3tan alpha

int tan x tan 2x tan 3x dx

int{1+tan x*tan(x+alpha)}dx=