निम्न समीकरण को हल कीजिए :
`|(x+2,x+6,x-1),(x+6,x-1,x+2),(x-1,x+2,x+6)|=0.`

Using the properties of determinants, find the value of x, if: {:|(x+2,x+6,x-1),(x+6,x-1,x+2),(x-1,x+2,x+6)|=0

Solve the following equations.|(x+2,x+6,x-1),(x+6,x-1,x+2),(x-1,x+2,x+6)|=0

निम्न समीकरण को हल कीजिए - tan^(-1)(x-1)+tan^(-1)(x)+tan^(-1)(x+1)=tan^(-1) 3 x

((x-2))/((x+2))+6((x-2)/(x-6))=1,x!=-2,6

(x+1)(x-3)(x+2)(x-4)+6=0

Solve (2x-3)/(x-1)+1=(6x-x^(2)-6)/(x-1)

If f(x) = |(x,x^2,x^3),(1,2x,3x^2),(0,2,6x)| , then f^(1)(x)=

Solve (2x-3)/(x-1)+1=(6x-x^2-6)/(x-1)dot

Solve (2x-3)/(x-1)+1=(6x-x^2-6)/(x-1)dot