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Two cells having emf's of 10 V and 8 V, ...

Two cells having emf's of 10 V and 8 V, and internal resistance of `1Omega`(each) are connected as shown with an external resistance of `8Omega` Find the current flowing through the circuit.

Text Solution

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Suppose that a current i flows through the external resistance (82) and it divides into two branches at the node B as `I_(1)` and `I-(2)`
Using KCL, `I_(1) + i_(2)= 1`` Using KVL
For Loop ABYXA
`(-i_(1))1+(i-i_(1))1=-10+8`
For Loop ABQPA`(-i_(1))1+(-i)8=-10`
On solving, we get
`i=(18)/(17)Aapprox1.06A`
`i=10-8i=(10-8.54)A=1.52A
`i_(2)=i-i_(1)=-0.46A`The negative sign for `i_(2)` means that its direction is opposite to the direction that we had assumed
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