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If two bulbs of 25 W and 100 W rated at ...

If two bulbs of 25 W and 100 W rated at 200 volts are connected in series across a 440 volts supply, then

A

100 watt bulb will fuse

B

25 watt bulb will fuse

C

none of the bulb will fuse

D

both the bulbs will fuse

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To solve the problem step by step, let's analyze the situation where two bulbs rated at 25 W and 100 W (both rated for 200 V) are connected in series across a 440 V supply. We need to determine which bulb will fuse. ### Step 1: Calculate the Resistance of Each Bulb The power \( P \) of a bulb is related to its voltage \( V \) and resistance \( R \) by the formula: \[ P = \frac{V^2}{R} \] From this, we can rearrange to find the resistance: \[ R = \frac{V^2}{P} \] **For the 25 W bulb:** \[ R_1 = \frac{200^2}{25} = \frac{40000}{25} = 1600 \, \Omega \] **For the 100 W bulb:** \[ R_2 = \frac{200^2}{100} = \frac{40000}{100} = 400 \, \Omega \] ### Step 2: Calculate Total Resistance in Series When resistors are in series, the total resistance \( R_t \) is the sum of the individual resistances: \[ R_t = R_1 + R_2 = 1600 \, \Omega + 400 \, \Omega = 2000 \, \Omega \] ### Step 3: Calculate the Current in the Circuit Using Ohm's Law, we can find the current \( I \) flowing through the circuit when connected to a 440 V supply: \[ I = \frac{V}{R_t} = \frac{440}{2000} = 0.22 \, \text{A} \] ### Step 4: Calculate the Power Dissipated by Each Bulb Now, we can calculate the power dissipated by each bulb using the formula: \[ P = I^2 R \] **For the 25 W bulb:** \[ P_1 = I^2 R_1 = (0.22)^2 \times 1600 = 0.0484 \times 1600 = 77.44 \, \text{W} \] **For the 100 W bulb:** \[ P_2 = I^2 R_2 = (0.22)^2 \times 400 = 0.0484 \times 400 = 19.36 \, \text{W} \] ### Step 5: Compare Dissipated Power with Rated Power Now we compare the power dissipated by each bulb with their rated power: - The 25 W bulb is dissipating 77.44 W, which exceeds its rated power of 25 W. Therefore, the 25 W bulb will fuse. - The 100 W bulb is dissipating 19.36 W, which is less than its rated power of 100 W. Therefore, the 100 W bulb will not fuse. ### Conclusion The 25 W bulb will fuse, while the 100 W bulb will not fuse. ---

To solve the problem step by step, let's analyze the situation where two bulbs rated at 25 W and 100 W (both rated for 200 V) are connected in series across a 440 V supply. We need to determine which bulb will fuse. ### Step 1: Calculate the Resistance of Each Bulb The power \( P \) of a bulb is related to its voltage \( V \) and resistance \( R \) by the formula: \[ P = \frac{V^2}{R} \] From this, we can rearrange to find the resistance: ...
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