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Two cells having emf's of 10 V and 8 V, ...

Two cells having emf's of 10 V and 8 V, respectively, are connected in series with a resistance of `24Omega` In the external circuit. Their internal resistances are `2Omega// V` (proportional to their emf's). Find the current in the circuit

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We determine the internal resistance of each of these cells
`r_(1) = 2Omega//V xx 10 V = 20Omega, r_(2) = 2Omega//V xx 8 V = 16Omega`
Total resistance in the circuit =` (24 + 16 + 20)Omega = 60Omega`
Current =` (18V)/(60omega)=0.3A`
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