Two wires made of a good conductor, having same area of cross-section and different lengths, are to be used as fuses. Show that the fuses will melt at the same value of current in each case

Two wires made of tinned copper having identical cross-section (=10^(-6)m^(2)) and lengths 10cm and 15cm are to be used as fuses. Sow that the fuses will melt at the same value of current in each case.

Two wires made of tinned copper having identical cross section ( = 10^(-6) m^(2)) and lengths 10 and 15 cm are to be used as fuses. Show that the fuses will melt at the same value of current in each case.

Two wires A and B are of same metal, have the same area of cross-section and have their lengths in the ratio 2 : 1 . What will be the ratio of currents flowing through them respectively when the same potential difference is applied across the length of each of them ?

There are two wires of the same metal of same area of cross section but having lengths in the ratio 2 : I. If same p.d. is applied across their ends, what will be the ratio of current in them?

Two wires of the same materical having equal area of cross-section have L and 2L. Their respective resistances are in the ratio

Two wires of same material and area of cross section but with lengths in the ratio 5:3 are strechted by the same force. The ratio of work done in two cases is

Two wires A and B are stretched by the same load. If the area of cross-section of wire 'A' is double that of 'B,' then the stress on 'B' is

Two wires are made having same length l and area of cross-section A. Wire 1 is made of copper and wire 2 is made of aluminium. It is given that the electrical conductivity of copper is more than that of aluminium. In this context, which one of the following statements is correct?

The area of cross-section of a metal wire is doubled, keeping its length same, then its resistance is: