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When two identical batteries of internal...

When two identical batteries of internal resistance `1Omega` each are connected in series across a resistor R, the rate of heat produced in R is `J_1`. When the same batteries are connected in parallel across R, the rate is ``J_2 = 2.25 J_2` then the value of R in `Omega` is

Text Solution

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`J_(1)=((2E)/(R+2))^(2)R`
`J_(2)=((2E)/(2R+1))^(2)R`
`(J_(1))/(J_(2))= 2.25solving R=4Omega`
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