N identical cells, each of emf `epsilon` and internal resistances r are joined in series. Out of these, n cells are wrongly connected, i.e. their terminals are connected in reverse order as required for series connection. If `epsilon_(o)` be the emf of the resulting battery and `r_(o)` be its internal resistance then for n `lt N//2`

Options

A. `epsilon_(0) = (N-n)epsilon,r_(o) = (N-n)r`
B. `epsilon_(0 )=(N-n)epsilon, r_(o) = (N-2n) r`
C. v `epsilon_(o)= (N-2n) epsilon, r_(o) = Nr`
D. `epsilon_(o) = (N-n)epsilon, r_(o) = Nr`

Answer

C