A battery of 10 V is connected to a resi...

A battery of 10 V is connected to a resistance of `20Omega` through a variable resistance R. If the variable resistance R is increased at the rate of `5Omega" min"^(-1)`, then the amount of charge that passes through the battery in 4 min is

120 coulomb

`120 log_(e) 2 coulomb`

`(120)/(log_(e)2) coulomb`

`(60)/ (log_(e) 2)coulomb`

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