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The maximum power dissipated by external...

The maximum power dissipated by external resistance R by a cell of an external omf E and internal resistance r is `E^(2)//4R` which is obtained for

A

`Rltr`

B

`Rltr`

C

`R=r`

D

any value of R.

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The correct Answer is:
To solve the problem of finding the condition for maximum power dissipated by an external resistance \( R \) in a circuit with a cell of EMF \( E \) and internal resistance \( r \), we can follow these steps: ### Step 1: Understand the Circuit We have a circuit consisting of a cell with an EMF \( E \) and an internal resistance \( r \). The external resistance connected to this cell is \( R \). ### Step 2: Write the Expression for Current The total resistance in the circuit is the sum of the internal and external resistances: \[ R_{\text{total}} = R + r \] The current \( I \) flowing through the circuit can be expressed using Ohm's law: \[ I = \frac{E}{R + r} \] ### Step 3: Write the Expression for Power Dissipated in the External Resistance The power \( P \) dissipated in the external resistance \( R \) can be calculated using the formula: \[ P = I^2 R \] Substituting the expression for \( I \): \[ P = \left(\frac{E}{R + r}\right)^2 R \] This simplifies to: \[ P = \frac{E^2 R}{(R + r)^2} \] ### Step 4: Maximize the Power To find the maximum power, we need to differentiate \( P \) with respect to \( R \) and set the derivative equal to zero: \[ \frac{dP}{dR} = 0 \] Using the quotient rule, we differentiate: \[ \frac{dP}{dR} = \frac{(R + r)^2 \cdot E^2 - E^2 R \cdot 2(R + r)}{(R + r)^4} \] Setting the numerator equal to zero: \[ (R + r)^2 E^2 - 2E^2 R(R + r) = 0 \] This simplifies to: \[ E^2 \left( (R + r)^2 - 2R(R + r) \right) = 0 \] Ignoring \( E^2 \) (since it cannot be zero), we have: \[ (R + r)^2 - 2R(R + r) = 0 \] ### Step 5: Solve the Equation Expanding and simplifying: \[ R^2 + 2Rr + r^2 - 2R^2 - 2Rr = 0 \] This reduces to: \[ -r^2 + R^2 = 0 \] Thus: \[ R^2 = r^2 \implies R = r \] ### Conclusion The maximum power is dissipated when the external resistance \( R \) is equal to the internal resistance \( r \). ### Final Answer The maximum power dissipated by the external resistance \( R \) occurs when \( R = r \). ---
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