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Three ammeters 1, 2, and 3 of resistance...

Three ammeters 1, 2, and 3 of resistances `R_(1). R_(2) and R_(3)` respectively are joined as shown. When some potential difference is applied across the terminals P and Q, their readings are `I_(1), I_(2) and I_(3)`, respectively. Then

A

`I_(1)=I_(2)`

B

`I_(1)R_(1)+I_(2)R_(2)=I_(3)R_(3)`

C

`(I_(1))/(I_(2))=(R_(3))/(R_(1))`

D

`(I_(2))/(I_(3))=(R_(3))/(R_(1)+R_(2))`

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The correct Answer is:
A, B, D
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