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If lambda(0) is the threshold wavelnegth...

If `lambda_(0)` is the threshold wavelnegth of a metal and `lambda` is the wavelength of the incident radiation, the maximum velocity of the ejected electron from the metal would be

A

`[ ( 2hc)/( m )((lambda_(0) - lambda)/( lambda_(0) lambda)) ]^(1//2)`

B

`[ ( 2hc)/( m )((lambda-lambda_(0) )/( lambdalambda_(0))) ]^(1//2`

C

`[ ( 2hc)/( m ) ( lambda - lambda_(0) ) ]^(1//2)`

D

`[ ( 2hc)/( m ) ( lambda_(0) - lambda) ]^(1//2)`

Text Solution

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The correct Answer is:
A
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