The reaction of chloroform with acetone gives

Options

A. chloral
B. chloretone
C. mesitylene
D. ethylidene chloride

Answer

To solve the question regarding the reaction of chloroform with acetone, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are chloroform (CHCl3) and acetone (CH3COCH3).

### Step 2: Understand the Role of the Base
The reaction occurs in the presence of a base, typically sodium hydroxide (NaOH). The base plays a crucial role in generating a reactive intermediate.

### Step 3: Formation of Carbanion
The base (OH⁻) abstracts a hydrogen atom from chloroform (CHCl3), leading to the formation of a carbanion. The reaction can be represented as:
\[ \text{CHCl}_3 + \text{OH}^- \rightarrow \text{CCl}_3^- + \text{H}_2O \]
This carbanion (CCl3⁻) is a strong nucleophile.

### Step 4: Nucleophilic Attack on Acetone
The carbanion (CCl3⁻) then attacks the electrophilic carbon of the carbonyl group in acetone (CH3COCH3). This results in the formation of an intermediate:
\[ \text{CCl}_3^- + \text{CH}_3\text{COCH}_3 \rightarrow \text{CH}_3\text{C(Cl}_3)\text{O}^- \]

### Step 5: Protonation to Form the Final Product
The negatively charged intermediate is then protonated (gains a hydrogen ion) to yield the final product:
\[ \text{CH}_3\text{C(Cl}_3)\text{O}^- + \text{H}^+ \rightarrow \text{CH}_3\text{CCl}_3\text{O} \]
This product is known as chloroformylacetone or chloroacetone.

### Step 6: Conclusion
Thus, the reaction of chloroform with acetone in the presence of a base results in the formation of chloroacetone.

### Final Answer
The product of the reaction of chloroform with acetone is **Chloroacetone**.

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