Which of the following compounds have more than one type of hybridisation for carbon?
(i) `HC-=CH`
(ii) `CH_(2)=CH-C-=CH`
(iii) `CH_(3)CH=CHCH_(3)`
(iv) `CH_(3)CH_(2)CH_(2)CH_(3)`

Options

A. (iii)
B. (i)
C. (ii) and (iii)
D. (i) and (iii)

Answer

To determine which of the given compounds have more than one type of hybridization for carbon, we will analyze each compound one by one.

### Step 1: Analyze Compound (i) `HC≡CH`
- The structure is: H-C≡C-H
- The carbon atoms are involved in a triple bond.
- Each carbon is bonded to one hydrogen atom and has a triple bond with the other carbon.
- Hybridization: Each carbon is sp hybridized (2 sigma bonds, 2 pi bonds).
- **Conclusion**: Both carbons are sp hybridized.

### Step 2: Analyze Compound (ii) `CH₂=CH-C≡CH`
- The structure is: H₂C=CH-C≡C-H
- The first carbon (C1) is bonded to two hydrogens and has a double bond with the second carbon (C2).
- The second carbon (C2) is bonded to one hydrogen and has a double bond with C1 and a single bond with C3.
- The third carbon (C3) is involved in a triple bond with the fourth carbon (C4).
- Hybridization:
- C1: sp² (3 sigma bonds)
- C2: sp² (3 sigma bonds)
- C3: sp (2 sigma bonds)
- C4: sp (2 sigma bonds)
- **Conclusion**: This compound has sp² and sp hybridization.

### Step 3: Analyze Compound (iii) `CH₃CH=CHCH₃`
- The structure is: CH₃-CH=CH-CH₃
- The first carbon (C1) is bonded to three hydrogens and has a single bond with C2.
- The second carbon (C2) is involved in a double bond with C3.
- The third carbon (C3) is involved in a double bond with C2 and has a single bond with C4.
- The fourth carbon (C4) is bonded to three hydrogens and has a single bond with C3.
- Hybridization:
- C1: sp³ (4 sigma bonds)
- C2: sp² (3 sigma bonds)
- C3: sp² (3 sigma bonds)
- C4: sp³ (4 sigma bonds)
- **Conclusion**: This compound has sp² and sp³ hybridization.

### Step 4: Analyze Compound (iv) `CH₃CH₂CH₂CH₃`
- The structure is: CH₃-CH₂-CH₂-CH₃
- All carbon atoms are connected by single bonds.
- Hybridization: All carbons are sp³ hybridized (4 sigma bonds).
- **Conclusion**: All carbons are sp³ hybridized.

### Final Conclusion:
The compounds that have more than one type of hybridization for carbon are:
- Compound (ii) `CH₂=CH-C≡CH` (sp² and sp)
- Compound (iii) `CH₃CH=CHCH₃` (sp² and sp³)

### Summary:
- **Compound (i)**: All sp
- **Compound (ii)**: sp² and sp (more than one type)
- **Compound (iii)**: sp² and sp³ (more than one type)
- **Compound (iv)**: All sp³