`H_(3)C-CH_(2)-underset(Br)underset(|)(C)H-CH_(3) overset(NaNH_(2))to`
Which are correct statement?

Options

A. 1-butene is Hofman product
B. 2-butene is saytzeff product
C. both are correct
D. none is correct

Answer

To solve the problem regarding the reaction of 2-bromobutane with sodium amide (NaNH2), we will analyze the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reactant**:
The given compound is 2-bromobutane, which can be represented as:
\[ \text{CH}_3-\text{CH}_2-\text{C}(\text{Br})-\text{CH}_3 \]

2. **Understand the Reagent**:
Sodium amide (NaNH2) is a strong base. It can deprotonate hydrogen atoms from the adjacent carbon atoms (alpha hydrogens) to the carbon bearing the bromine atom.

3. **Possible Deprotonation**:
The base (NaNH2) can abstract a proton from either of the two adjacent carbon atoms (the one on the left or the one on the right of the carbon attached to Br):
- If it abstracts a proton from the left carbon (CH2), the double bond will form between the left carbon and the carbon with Br, leading to the formation of 1-butene.
- If it abstracts a proton from the right carbon (CH3), the double bond will form between the carbon with Br and the right carbon, leading to the formation of 2-butene.

4. **Determine the Products**:
- **Hofmann Product**: This is the less substituted alkene, which in this case is 1-butene (formed by deprotonating the left carbon).
- **Saytzeff Product (Zaitsev's Rule)**: This is the more substituted alkene, which is 2-butene (formed by deprotonating the right carbon).

5. **Conclusion**:
- The reaction produces both 1-butene (Hofmann product) and 2-butene (Saytzeff product).
- Therefore, the correct statements regarding the products of the reaction are:
- 1-butene is a Hofmann product.
- 2-butene is a Saytzeff product.
- Both statements are correct.

### Final Answer:
- The correct options are:
1. 1-butene is a Hofmann product.
2. 2-butene is a Saytzeff product.
3. Both are correct.