If sucrose iss treated with conc. `H_(2)SO_(4)`, the product formed is

Options

A. `CO_(2)`
B. `C`
C. `CO`
D. `H_(2)O`

Answer

To determine the product formed when sucrose is treated with concentrated sulfuric acid (H₂SO₄), we can follow these steps:

### Step 1: Understand the Composition of Sucrose
Sucrose is a disaccharide composed of glucose and fructose. Its chemical formula is C₁₂H₂₂O₁₁.

### Step 2: Identify the Nature of Concentrated H₂SO₄
Concentrated sulfuric acid is a strong dehydrating agent. This means that it has the ability to remove water from other substances.

### Step 3: Reaction of Sucrose with Concentrated H₂SO₄
When sucrose is treated with concentrated H₂SO₄, the acid removes water from the sucrose molecule. This dehydration process leads to the formation of carbon and water.

The reaction can be summarized as:
\[ \text{C}_{12}\text{H}_{22}\text{O}_{11} + \text{H}_2\text{SO}_4 \rightarrow 12\text{C} + 11\text{H}_2\text{O} \]

### Step 4: Identify the Products
From the reaction, we see that the products formed are:
- Carbon (in the form of black graphitic carbon)
- Water (H₂O)

### Conclusion
Thus, when sucrose is treated with concentrated sulfuric acid, the main product formed is carbon (C) along with water (H₂O).

### Final Answer
The product formed is carbon (C) and water (H₂O).

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