Does the hydrolysis of `XeF_(6)` leads to a redox reaction?

Explanation

Complete hydrolysis of `XeF_(6)` gives `XeO_(3)`
`Xe^(-6)F_(4) + 3H_(2)O—>Xe^(-6)O + 6HF`
On the other hand, partial hydrolysis of `Xef_(4)` gives `XeO_(2)F_(2)`, and `XeO_(2)F_(2)`
`Xe^(-6)F_(4)^(-1) + H_(2)^(-1)O^(-2)—>Xe^(-6)O^(-2)F_(4)^(-1) + 2H^(+1)F^(-1)`