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The comcept of redistribution of energy ...

The comcept of redistribution of energy in different orbitals of an atom associated with different energies to give new orbitals of equal (or somethimes it may be non-equal) energy oriented in space in definite directions is called hybridization and formed new orbitals are called hybrid orbitals. The bonds formed by such orbitals are called hybrid bonds. The process of mixing of orbitals itself requires some energy. Thus, some additional energy, is needed for the hybridisation (mixing) of atomic orbitals.
Q. Which of the following statement is correct?

A

In `BrF_(3)`, maximum three halogen atoms can lie in same plane

B

In `CH_(2)SF_(2)(CH_(3))_(2)` molecule all hydrogen atoms which bonded to `s-sp^(2)`overlapping, lie in equitorial plane

C

In `OSCl_(4), Cl-S-Cl` equitorial bond angle is greater than `120^(@)`

D

Molecules `IOF_(5) and XeO_(2)F_(4)` have similar shape but have different number of lone pairs in whole molecule

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The correct Answer is:
B

(a) `implies ` Maximum number of atoms that can lie in a plane =4
(b) `implies` Hydrogen atoms bonded by `1s-sp^(2)` overlapping lie in axial
(c) `impliesangleCl-S-Cl` is less than `120^(@) ` due to shifting of s-character in S=O bond. (d)
No. of lone pairs =17 : No.of lone pairs=16
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The comcept of redistribution of energy in different orbitals of an atom associated with different energies to give new orbitals of equal (or somethimes it may be non-equal) energy oriented in space in definite directions is called hybridization and formed new orbitals are called hybrid orbitals. The bonds formed by such orbitals are called hybrid bonds. The process of mixing of orbitals itself requires some energy. Thus, some additional energy, is needed for the hybridisation (mixing) of atomic orbitals. Q. In neutral moleule XeO_(n_(1)) F_(n_(2)) , central atom has no lone pair and ratio of (n_(2))/(n_(1)) is two, then which of the following orbitals does not participate in bonding ( n_(1) and n_(2) are natural numbers):

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