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Consider the following table Than ...

Consider the following table

Than calculate value of experssion `|(n_(1)+n_(2)+n_(3)+n_(4))/(m_(1)+m_(2)+m_(3)+m_(4))|^(2)`.

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The correct Answer is:
`16`
compound
`SX_(2)` `n_(1)=2` `m_(1)=2`
`PX_(3)` `n_(2)=3` `m_(2)=1`
`SiX_(4)` `n_(3)=4` `m_(3)=0`
`AlX_(3)` `n_(4)=3` `m_(4)=0`
`|(2+3+4+3)/(2+1)|^(2)=|(12)/(3)|^(2)=|4|^(2)=16`
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