Consider two covalent compounds `AL_(n_(1)) and BL_(n_(2))`, if central atom (A) of first compounds has total six electron pairs and central atom (B) of second compound contains total five electron pairs in its valence shell and both compounds are planar and non-polar then calculate value of experssion `(n_(1)-n_(2))^(2)`.
[Where `n_(1) and n_(2)` are number of monovalent surrounding atom (L)]

Answer

`4`

Explanation

`implies AL_(n_(1))`: implies` Number of electron pair on A=6
`implies` Non-polar
`implies` planar
Hence `n_(1)=4`
`implies BL_(2):
`implies` Number of electron pair on B=5
`implies` Non-polar
`implies` planar
Hence `n_(2)=2`
`(n_(1)-n_(2))^(2)=(4-2)^(2)=4`