Consider the following ligands `NH_(2)^(-),` acac, `OH^(-)`, Gly, `O_(2)^(-)`, Phen, DMG, `NO_(2)^(-),CO_(3)^(2-),Cl^(-),CH_(3)COO^(-),en,SO_(4)^(2-)`. Then calculate vlaue of "P+Q-R-S" here
P: total number of ligands which act as bridging as well as monodentate only.
Q: Total number of flexidentate ligands.
R: Total number of bidentate ligands only
S: Total number of unsymmetrical bidentate ligands.

Answer

1

Explanation

`P=NH_(2)^(-),O_(2)^(-),OH^(-),Cl^(-)=4`
`Q=SO_(4)^(2-),NO_(2)^(-),CO_(3)^(2-),CH_(3)COO^(-)=4`
Ren,acac, Phen, DMG, Gly=5
S=DMG, Gly=2
4+4-5-2=1