`Br_(2)+NaOH overset(R.T.) to Y+Z`
If Y gives precipitate with `AgNO_(3)`, then Z does not undergo reaction with:

Options

A. `Cr^(3+)(aq.)`
B. `Fe^(2+)(aq.)`
C. `Al^(3+)(aq.)`
D. `Sn^(2+)(aq.)`

Answer

C

Explanation

`Br_(2)+NaOH to NaBr(Y)+NaBrO(Z)`
NaBrO is an oxidising agent which can oxidize
`Cr^(3+) to Cr^(6+),Fe^(2+) to Fe^(3+),Sn^(2+)toSn^(4+)`
but oxidation of `Al^(3+)` is not possible.