Select correct set of species which can't react with water but react with NaOH,
(i) `NO_(2)`
(ii) `P_(4)`
(iii) `Al`
(iv) `I_(2)`

Options

A. Only (iv)
B. (iii) and (iv)
C. (ii), (iii) and (iv)
D. all (i), (ii), (iii) and (iv)

Explanation

To solve the problem of selecting the correct set of species that cannot react with water but can react with NaOH, we will analyze each of the given species: \( NO_2 \), \( P_4 \), \( Al \), and \( I_2 \).

### Step-by-Step Solution:

1. **Analyze \( NO_2 \)**:
- \( NO_2 \) (Nitrogen Dioxide) reacts with water to form nitrous acid (\( HNO_2 \)) and nitric acid (\( HNO_3 \)).
- **Conclusion**: \( NO_2 \) reacts with water.

2. **Analyze \( P_4 \)**:
- \( P_4 \) (White Phosphorus) is insoluble in water and does not react with it.
- **Conclusion**: \( P_4 \) does not react with water.

3. **Analyze \( Al \)**:
- \( Al \) (Aluminium) is a reactive metal, but it forms a protective oxide layer when exposed to air. In pure water, it does not react significantly due to this oxide layer.
- **Conclusion**: \( Al \) does not react with water.

4. **Analyze \( I_2 \)**:
- \( I_2 \) (Iodine) is also insoluble in water and does not react with it.
- **Conclusion**: \( I_2 \) does not react with water.

5. **Reactions with NaOH**:
- **For \( NO_2 \)**: It reacts with NaOH to form sodium nitrite (\( NaNO_2 \)) and sodium nitrate (\( NaNO_3 \)).
- **For \( P_4 \)**: It reacts with NaOH to form phosphine and sodium phosphide.
- **For \( Al \)**: It reacts with NaOH to form sodium aluminate and hydrogen gas.
- **For \( I_2 \)**: It reacts with NaOH to form sodium iodide (\( NaI \)) and sodium hypoiodite (\( NaOI \)).

### Final Conclusion:
The species that do not react with water but do react with NaOH are \( P_4 \), \( Al \), and \( I_2 \). Therefore, the correct set of species is:

**Answer: \( P_4 \), \( Al \), \( I_2 \)**.