A very dilute acidic solution of `Cd^(2+)&Ni^(2+)` gives only yelllwo ppt. of CdS on passing `H_(2)S`, this is due to:

Options

A. solubility product `(K_(sp))` of CdS is more than that of NiS.
B. Solubility product `(K_(sp))` of CdS is less than that of NiS.
C. `Cd^(2+)` belong to II B group while `Ni^(2+)` belongs to `IV`th group
D. CdS is insoluble in yellow ammonium sulphide (YAS).

Answer

B

Explanation

Basic radicals are classified on the basic of increasing order of `K_(sp).Cd^(2+)` in II group while `Ni^(2-)` in IV group.