" (iii) "4x^(2)+4bx-(a^(2)-b^(2))=0quad " (UP "2019)

Solve the following quadratic equation for x:4x^(2)+4bx-(a^(2)-b^(2))=0

Find the roots of the following equation 4x^(2)+4bx-(a^(2)-b^(2))=0 by the method of completing the square.

Solve by factorization: 4x^(2)+4bx-(a^(2)-b^(2))=0

Find the roots of each of the following equations, if they exist, by applying the quadratic formula: 4x^(2)+4bx-(a^(2)-b^(2))=0

Solve the quadratic equation 4x^2+4bx-(a^2-b^2)=0

The radius of the circle 3x^(2)+ by^(2) + 4bx - 6by + b^(2) = 0

If alpha,beta,gamma,delta are the roots of the equation x^(4)+Ax^(3)+Bx^(2)+Cx+D=0 such that alpha beta gamma delta =k and A,B,C,D are the roots of x^(4)-2x^(2)+4x^(2)+6x-21=0 such that A+B=0 then the value of (C)/(A), is

The radius of the circle 3x ^(2) + by ^(2) + 4 bx - 6by + b ^(2) =0 is