`cos^(-1)((3cosx-4sinx)/(5))`

(d)/(dx)[sin^(-1)((3cosx+4sinx)/(5))]=

cos^(-1)((3cosx-2sinx)/(sqrt(13)))

Express in simplest form: cos^(-1)(3/5cosx+4/5sinx)

Simplify each of the following: cos^(-1)(3/5cosx+4/5sinx) , where -(3pi)/4lt=xlt=pi/4

Find the simplified form of cos^(-1)(3/5cosx+4/5sinx),"where "x in[(-3pi)/4,pi/4] .

Simplify each of the following: cos^(-1)(3/5cosx+4/5sinx) , where -(3pi)/4lt=xlt=pi/4 sin^(-1)(5/(13)cosx+(12)/(13)sinx)

Simplify : cos^-1{3/5cosx+4/5sinx}

tan^(-1)((cosx+sinx)/(cos x-sinx))