A `100 Omega` resistance is connected in series with a `4 H` inductor. The voltage across the resistor is `V_(R) = 2 sin (1000 t) V`. The voltage across the inductors is

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find amplitude of the voltage across the inductor.

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find the inductive reactance

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find the expression of circuit current

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expessinocircuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

An alternating voltage is connected in series with a resistor R and an inductor L. If the potential drop across the resistor is 200 V and across the inductor is 150 V, then what is the applied voltage ?

An inductor and a resistor are connected to an ac supply of 50 V and 50 Hz. If the voltage across the resistor is 40 V the voltage acron the inductor will be