A body of mass `1//4 kg` is in `SHM` and its displacement is given by the relation `x = 0.05 Sin(20t +(pi)/(2))m`. If is in seconds, the maximum force acting on the particle is

A particle of mass 4 kg is executing S.H.M. Its displacement is given by the equation Y=8 cos[100t+pi//4] cm. Its maximum kinetic energy is

A particle of mass 4 kg is executing S.H.M. Its displacement is given by the equation Y=8 cos[100t+pi//4] cm. Its maximum kinetic energy is

A particle of mass 4 kg is excuting S.H.M. Its displacement is given by the equation y=8 cos[100t +pi//4] cm . Its maximum kinetic energy is,

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

A body of mass 1 kg is performing linear S.H.M. its displacement x (cm) at t (second) is given by x = 6 sin (100 t + (pi) /4) .Maximum kinetic energy of the body is

A body of mass 3 kg acted upon by a constant force is displaced by 's' meter, given by the relation s=(1)/(3)t^(2) , where t is in second. Work done by the force in 2 seconds is