`8ab^2-18a^3`

Prove that a^6+8a^3+27-18a^3=(a^2+2a+3)(a^4+4a^2+9-2a^3-6a-3a^2)

Subtract the sum of 12ab-10b^2 -18a^2 and 9ab + 12 b^2+ 14a^2 " from the sum of " ab + 2b^2 and 3b^2-a^2 .

Subtract the second polynomial from the first: 2ab^2 +3a^2 b -4ab , 3ab-8ab^2 +2a^2 b .

Carry out the following division : 72a^3b^4c^5 by 8ab^2c^3 .

Factorise completely : 8x^2 y - 18y^3

8x^2 - 18 =

Simplify (a^(2) - 8ab - 5) + (3ab - 4a^(2) + 8)