the sum of the `n` terms of `A.P.` is `4n(n-1)` then the sum of their squares is:

If the sum of n terms of an A.P is cn (n-1)where c ne 0 then the sum of the squares of these terms is

If the sum of n terms of an A.P is cn (n-1)where c ne 0 then the sum of the squares of these terms is

If the sum of n terms of an A.P is cn (n-1)where c ne 0 then the sum of the squares of these terms is

The sum of the first three terms of an A.P. is 9 and the sum of their squares is 35. The sum to first n terms of the series can be

If the sum of first n terms of an A.P. is cn^(2) then the sum of squares of these n terms is

If the sum of first n terms of an A.P. is cn^(2) then the sum of squares of these n terms is

If the sum of first n terms of an A.P. is cn^(2) , then the sum of squares of these n terms is :