2 cubes each of volume `64 c m^3`are joined end to end. Find the surface area of the resulting cuboid.

Explanation

Let side of the cubes in cm is `a`.Then,
`a^3 = 64=> a = 4`

If we join these two cubes end to end, then surface area of resulting cuboid will have `10` faces
as two internal faces are common will not be included in the cuboid.

Please refer to video for graphical explanation.

So, surface area of resulting cuboid, `A = 10**`Surface area of each face

`A = 10**(4)^2 = 160cm^2`