From the graph of `y=x^(2)-4`, draw the graph of `y=(1)/(x^(2)-4)`.

Explanation

`y=f(x)=x^(2)-4` is an upward parabola having vertex at (0, -4).

Since the function is even, let us draw the graph of `y=f(x)` for `x in [0, oo)-{2}`.
For `[0,2),x^(2)-4` increases from -4 to 0.
So `(1)/(x^(2)-4)` decreases from -1/4 to `-oo`.
For `(2, oo), x^(2)-4` increases from 0 to `oo`.
So `(1)/(x^(2)-4)` decreases from `oo` to 0.
So the graph of `y=f(x) ` for `x in [0, oo)-{2}` is as shown in the following figure.

Since `y=g(x)` is an even function, the graph for R-{-2,2} can be drawn as shown in the following figure.