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Two adjacent vertices of a square are (1...

Two adjacent vertices of a square are (1, 2) and `(-2,6)` Find the other vertices.

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Given two adjacent vertices are A (1,2) and B(-2,6). Then,
AB = 5
Also, the slope of AB is
`m_(AB) = (6-2)/(-2-1) = -(4)/(3)`
` "Slope of AD" = (3)/(4) = "tan " theta`
The coordinates of D and D' are
`(1+-5 "cos" theta, 2+-5"sin"theta) -= (1+-5(4)/(5), 2 +- 5(3)/(5))`
or D(5,5) and D'(-3-1)
Similarly, the coordinates of C and C' are
`(-2+-5 "cos" theta, 6+-5"sin"theta) -= (-2+-5(4)/(5), 6 +- 5(3)/(5))`
or C(2,9) and C'(-6,3)
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