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The angle between the diagonals of a qua...

The angle between the diagonals of a quadrilateral formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2` and `x/b+y/a=2` is (a) `pi/4` (b) `pi/6` (c) `pi/3` (d) `pi/2`

A

`(pi)/(4)`

B

`(pi)/(2)`

C

`(pi)/(3)`

D

`(pi)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
B
Clearly, distance between the parallel lines `(x)/(a)+(y)/(b) = 1 " and " (x)/(a) + (y)/(b) = 2 " is same as the distance between the parallel lines "(x)/(b)+(y)/(a) = 1 " and " (x)/(b)+(y)/(b) = 2`.
Therefore, quadrilateral is rhombus.
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