If `(x , y)` is a variable point on the line `y=2x` lying between the lines `2(x+1)+y=0` and `x+3(y-1)=0` , then `x in (-1/2,6/7)` (b) `x in (-1/2,3/7)` `y in (-1,3/7)` (d) `y in (-1,6/7)`

Options

A. `x in (-1//2, 6//7)`
B. `x in (-1//2, 3//7)`
C. `y in (-1, 3//7)`
D. `y in (-1, 6//7)`

Answer

B, D

Explanation

Solving y=2x, 2(x+1) + y = 0, we get x = -1/2, y=-1. Solving y=2x, x+3(y-1)=0, we get x=3/7, y=6/7.