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Given three straight lines 2x+11 y-5=0,2...

Given three straight lines `2x+11 y-5=0,24 x+7y-20=0,` and `4x-3y-2=0` . Then, they form a triangle one line bisects the angle between the other two two of them are parallel

A

they from a triangle

B

they are concurrent

C

one line bisects the angle between the other two

D

two of them are parallel

Text Solution

Verified by Experts

The correct Answer is:
C
For the two lines 24x+7y-20=0 and 4x-3y-2=0, the angle bisectors are given by
`(24x+7y-20)/(25) =+-(4x-3y-2)/(5)`
Taking positive sign, we get
2x+11y-5=0
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CENGAGE-STRAIGHT LINES-Exercise (Multiple)
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  14. The lines x+y-1=0,(m-1)x+(m^2-7)y-5=0, and (m-2)x+(2m-5)y=0 are concur...

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