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The equation of a straight line passing through the point (2, 3) and inclined at an angle of `tan^(-1)(1/2)` with the line `y+2x=5` `y=3` (b) `x=2` `3x+4y-18=0` (d) `4x+3y-17=0`

A

y=3

B

x=2

C

3x+4y-18=0

D

4x+3y-17=0

Text Solution

Verified by Experts

The correct Answer is:
B, C
Let the slope of required line be m. Then
`(1)/(2) = |(m-(-2))/(1+(-2)m)|`
`"or " m=-(3)/(4) " and " oo`
Hence, the equation of line is y-3=-(3/4) (x-2) and x=2.
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