Home
Class 12
MATHS
The sides of a triangle ABC lie on the l...

The sides of a triangle ABC lie on the lines `3x + 4y = 0, 4x +3y =0` and `x =3` . Let `(h, k)` be the centre of the circle inscribed in `triangleABC`. The value of `(h+ k)` equals

Text Solution

Verified by Experts

The correct Answer is:
0
The equation of the angle bisector of angle A is
`(3x+4y)/(5) = +-(4x+3y)/(5) " or " x=+-y`

The equation of internal bisectors is x=-y
Since h and k lie on the line x = -y, we have
h+k=0
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    CENGAGE|Exercise JEE Main Previous Year|9 Videos

  • STRAIGHT LINES

    CENGAGE|Exercise JEE Advanced Previous Year|4 Videos

  • STRAIGHT LINES

    CENGAGE|Exercise Exercise (Matrix)|8 Videos

  • STRAIGHT LINE

    CENGAGE|Exercise Multiple Correct Answers Type|8 Videos

  • THEORY OF EQUATIONS

    CENGAGE|Exercise JEE Advanced Previous Year|9 Videos

Similar Questions

Explore conceptually related problems

The sides of a triangle ABC lie on the lines 3x+4y=0,4x+3y=0 and x=3. Let (h,k) be the centre of the circle inscribed in /_ABC. The value of (h+k) equals

Area of triangle formed by straight lines 3x - y = 3, x - 2y + 4 =0 and y =0 is

The triangle formed by the lines x+y=0,3x+y=4,x+3y=4 is

Find the orthocenter of the triangle formed by the lines x + 2y = 0, 4x + 3y - 5 =0, 3x + y = 0 .

Area of triangle formed by straight line 4x - 3y + 4 =0, 4x + 3y - 20 = 0 and x-axis is

Let the points of intersections of the lines x -y +1 = 0, x -2y + 3 = 0 and 2x -5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is _______ .

Let the points of intersections of the lines x -y +1 = 0, x -2y + 3 = 0 and 2x -5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is _______ .

The sides of a triangle are 3x + 4y, 4x + 3y and 5x+5y units, where x gt 0, y gt 0 . The triangle is

The centre of circle 2x^(2)+2y^(2)+30x+40y+3=0 is (h,k) then the value of h+k is equal