Home
Class 12
MATHS
The line y=(3x)/4 meets the lines x-y=0 ...

The line `y=(3x)/4` meets the lines `x-y=0` and `2x-y=0` at points `Aa n dB` , respectively. If `P` on the line `y=(3x)/4` satisfies the condition `P AdotP B=25 ,` then the number of possible coordinates of `P` is____

Text Solution

Verified by Experts

The correct Answer is:
3

Point P which lies on the line y=3x/4 can be chosen as P(h, 3h/4).
If `theta` is the angle that the line y=3x/4 makes with the positive direction of the x-axis, then
`"tan " theta = (3)/(4) " or cos " theta =(4)/(5) " and sin" theta = (3)/(5)`
Now, the coordinates of points A and B which lie on the line y=3x/4 can be chosen as
`A-=(h+(4r_(1))/(5), (3h)/(4) + (3r_(1))/(5)) " and "B-=(h+(4r_(2))/(5), (3h)/(4) + (3r_(2))/(5))`
Since A lies on the line x-y+1 =0, we have
`(h+(4r_(1))/(5)) -((3h)/(4) + (3r_(1))/(5)) +1 =0`
`"or " r_(1) = (-5)/(4)(h+4)`
Since B lies on the line 2x-y-5=0, we have
`2(h+(4r_(2))/(5))- ((3h)/(4) + (3r_(2))/(5))-5=0`
`"or " r_(2) = (-5)/(4)(h-4)`
According to the given condition, we have
`PA * PB =25`
`i.e., |r_(1)| * |r_(2)| = 25`
`i.e., (25)/(16)(h^(2) -16) = +- 25`
`i.e., h^(2) = 16+-16 = 32, 0`
`i.e., h=+-4sqrt(2), 0`
Hence, the required points are (0, 0), `(4sqrt(2), 3sqrt(2)), " and " (-4sqrt(2), -3sqrt(2)).`
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    CENGAGE|Exercise JEE Main Previous Year|9 Videos
  • STRAIGHT LINES

    CENGAGE|Exercise JEE Advanced Previous Year|4 Videos
  • STRAIGHT LINES

    CENGAGE|Exercise Exercise (Matrix)|8 Videos
  • STRAIGHT LINE

    CENGAGE|Exercise Multiple Correct Answers Type|8 Videos
  • THEORY OF EQUATIONS

    CENGAGE|Exercise JEE Advanced Previous Year|9 Videos

Similar Questions

Explore conceptually related problems

The line y=(3x)/(4) meets the lines x-y+1-0 and 2x-y=5 at A and B respectively.Coordinates of P on y=(3x)/(4) such that PA*PB=25 .

The lines 3x-4y=9 and y=0 meet at :

If the line y=mx meets the lines x+2y-1=0 and 2x-y+3=0 at the same point, then m is equal to

A line through the point P(2,-3) meets the lines x-2y+7=0 and x+3y-3=0 at the points A and B respectively.If P divides AB externally in the ratio 3:2 then find the equation of the line AB.

A line intersects the straight lines 5x-y-4=0 and 3x-4y-4=0 at A and B ,respectively.If a point P(1,5) on the line AB is such that AP:PB=2:1 (internally),find point A.

A line intersects the straight lines 5x - y - 4 = 0 and 3x - 4y - 4 = 0 at A and B respectively. If a point P (1, 5) on the line AB is such that AP : PB = 2:1 (internally), find the point A.

The lines x-y-2=0,x+y-4=0,x+3y=6 meet at the point

A straight line through the point A(1,1) meets the parallel lines 4x+2y=9&2x+y+6=0 at points P and Q respectively.Then the point A divides the segment PQ in the ratio: