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A ray of light along x+sqrt(3)y=sqrt(3) ...

A ray of light along `x+sqrt(3)y=sqrt(3)` gets reflected upon reaching x-axis, the equation of the reflected ray is

A

`y=x+sqrt(3)`

B

`sqrt(3)y =x-sqrt(3)`

C

`y =sqrt(3)x-sqrt(3)`

D

`sqrt(3)y= x-1`

Text Solution

Verified by Experts

The correct Answer is:
B
`"Slope of " x+sqrt(3)y = sqrt(3) is -(1)/(sqrt(3)) = m_(1)` (let)

So, tan `theta = -(1)/(sqrt(3))`
`theta = 150^(@)`
So, slope of reflected ray `="tan" 30^(@) = (1)/(sqrt(3))`
So, equation of reflected ray is
`y-0 = (1)/(sqrt(3))(x-sqrt(3))`
`"or " sqrt(3) y =x-sqrt(3)`
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