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(log)3(1+1/3)+(log)3(1+1/4)+(log)3(1+1/5...

`(log)_3(1+1/3)+(log)_3(1+1/4)+(log)_3(1+1/5)+ddot+(log)_3(1+1/(242))` when simplified has the value equal to: 2 (b) 4 (c) 6 (d) `(log)_2 16`

A

2

B

4

C

6

D

`log_(2)16`

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